If the order of the outer loop is A and of the inner loop is B, then the total efficiency is O(AB)
What is the Big-Oh efficiency of two nested for-loops?
I don't know much about it, but maybe this website can help.
http://msdn.microsoft.com/library/defaul...
Reply:O(n^2)
Reply:Assuming for code is as the following:
for i-%26gt; 1 to n {
for j-%26gt; 1 to n { }
}
For the first for-loop will be executed n times. For each of the statement of the outer loop, there will be n times execution of the inner loop.
Hence, the big-oh of the following code is O(n^2)
Reply:Assuming that the loop is:
for (int a = 0; a %26lt; 5; a++) {
for (int b = 0; b %26lt; a; b++) {
}
}
The O should be n^2. This is because the value of b is depending on a. Which means a is being used twice.
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